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Length of 64 bits values #7

@piranna

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@piranna

I have been doing some maths and seems to me that 64bits numbers will need 10 bytes to represent them instead of 9 as we were talking about...

bytes = ceil(bits / 7)

  7 bits / 7 =  1    byte
  8 bits / 7 =  1.14 bytes -> 2 (+1 byte)
 16 bits / 7 =  2.28 bytes -> 3
 24 bits / 7 =  3.42 bytes -> 4
 32 bits / 7 =  4.57 bytes -> 5
 40 bits / 7 =  5.71 bytes -> 6
 48 bits / 7 =  6.85 bytes -> 7
 56 bits / 7 =  8    bytes
 64 bits / 7 =  9.14 bytes -> 10 bytes (+2)
...
112 bits (14 bytes) / 7 = 16    bytes
120 bits (15 bytes) / 7 = 17.14 bytes -> 18 bytes (+3)
128 bits (16 bytes) / 7 = 18.28 bytes -> 19 bytes

And so on... I think the 64 bits version is wrong due to that, what do you think?

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